Graph a line that contains the point (-7,-4) and has a slope of -2/3.

his requires the point slope formula or just substituting.

Let's do the point slope first

y-y1=m(x-x1) y1 is the y value of the ordered pair and x1 is the x value. m is the slope

y-8=1.2(x-7) Be careful with the signs. If the y value were -8, the left side would be y- -8 or y+8

Now distribute

y-8=(1.2*x) -8.4 (1.2*7)

add 8 to both sides

y=1.2x -0.4 That is the equation of the line.

Step-by-step explanation:

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )