Write the equation of a line in slope intercept form that is parallel to y=4/3x-7 and contains the point (5,-8) WILL GIVE BRAINLIEST

Answer;

The equation of the line is

3y = 4x + 4

Explanation;

Mathematically we can write the equation of a straight line in the form

y = mx + c

where m is the slope

Since the old line would parallel to the new line, then they have the same slope

This means that the slope of the new line will be 4/3

Now, we had yet slope and a point, we need to write the equation of the line

mathematically;

y- y1 = m(x - x1)

In this case m = 4/3, (x1,y1) = (5,-8)

Thus;

y+ 8 = 4/3(x-5)

y+ 8 = 4/3x -20/3

y = 4/3x -20/3 + 8

Multiply through by 3

3y = 4x -20 + 24

3y = 4x + 4

p = 6s

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b