The lengths of salamanders have a normal distribution with mean 15cm, and standard deviation 2cm. What is the probability a salamander has length between 12.2cm and 16.5cm

The probability a salamander has a length between 12.2cm and 16.5cm is 0.6930

Step-by-step explanation:

We start by finding the z-score of each

Mathematically;

z-score = (x - mean)/SD

for 12.2 cm

z-score = (12.2 - 15)/2 = -2.8/2 = -1.4

For 16.5 cm

z-score = (16.5 -15)/2 = 1.5/2 = 0.75

So the probability we want to calculate is;

P( -1.4 < z < 0.75)

we can calculate this using the normal distribution table

Mathematically;

P( -1.4 < z < 0.75) = P( z < 0.75) - P( z < -1.4)

= 0.2263 + 0.30738

= 0.69262

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!