Evaluate the following expression when a = -3, b = 2, c = 5, and
d= -4.
4c + d

-24

Step-by-step explanation:

this is how I think it should be done

Solution:

4c+d

4×5(c)-4(d)

20+-4

=-24

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.