Test the null hypothesis that there is no difference between the estimates of the two garages. Be sure to specify the null and alternative hypotheses, the test statistic with degrees of freedom, and the P-value. What do you conclude using the 0.05 significance level

t = [ (x1' - x2' ) - d ] / SE . p < 0.05 suggests means are equal, p > 0.05 suggests means are unequal.

Step-by-step explanation:

Null Hypothesis [H0] : There is no difference between average estimates of two garages, M1 = M2

Alternate Hypothesis [H1] : There is difference between average estimates of two garages, M1  ≠ M2

Hypothesis can be tested by t test

t = [ (x1' - x2' ) - d ] / SE , where :-

x1' & x2' are sample means, SE = sqrt[ (s1^2/n1) + (s2^2 /n2) ] , d is the hypothesized difference between population means, and SE is the standard error ie 0 here

If the p value corresponding to calculated t value is < p value as per significance level (0.05) : We reject null hypothesis & state that M1  ≠ M2

If the p value corresponding to calculated t value >  p value as per significance level (0.05) : We accept null hypothesis & state that M1 = M2

answer: the is put the 450

step-by-step explanation:

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).