Two families go to the theatre the Smith family of three adults and four children pay £67 the Jones family of five adults and six children pay £106 work out the cost of an adult ticket and the cost of a child ticket in your working at a stand for an adult ticket and C stand for child ticket

adult = $11

Child = $8.5

Step-by-step explanation:

Let the cost of an adult ticket be a

Let the cost of child ticket be c.

From the question,

3a + 4c = $67 i

5a + 6c = $106 ii

Multiply equation I by 5

Multiply equation ii by 3

15a + 20c = $335

- 15a + 18c = $318

2c = $17

C = $17/2 = $8.5

Put the value of c into

3a + 4c = $67

3a + 4($8.5) = $67

3a + $34 = $67

3a = $67 - $34

3a = $33

a = $11

Cost of adult ticket = $11

cost of child ticket = $8.5

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.