Coach Right is looking at his students' running times in order to place students into running groups. He is working on forming a group that matches Jim's pace of 4 miles in 38 minutes. Which of these student times would fit into a group that runs at the exact same rate as Jim?

Complete question :

Coach Right is looking at his students' running times in order to place students into running groups. He is working on forming a group that matches Jim's pace of 4 miles in 38 minutes. Which of these student times would fit into a group that runs at the exact same rate as Jim? Prax ran 6 miles in 57 minutes. Jose ran 5 miles in 45.5 minutes. Sandy ran 7 miles in 66.5 minutes. Zynep ran 3 miles in 27 minutes

Prax and sandy

Step-by-step explanation:

Given that:

Jim's pace = 4 miles in 38 minutes

Jim's rate = Distance covered / time.

Rate = 4 / 38 = 0.1052631 miles /min

Prax ran 6 miles in 57 minutes:

Prax rate : 6miles / 57 mins = 0.1052631

Jose ran 5 miles in 45.5 minutes:

Jose's rate = 5 miles / 45.5 = 0.1098901 miles /

minute

Sandy ran 7 miles in 66.5 minutes:

Sandy's rate = 7 / 66.5 = 0.1052631 miles / minutes

Zynep ran 3 miles in 27 minutes:

Zynep's rate : 3 / 27 = 0.1111111 miles / minutes

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl