Two men can do a work in 4 days and 6 days respectively how many days will it take if they work togatherpls tell with steps ill mark brainlist

The answer is 12/5 days

Step-by-step explanation:

The First Man (FM) takes 4 days to complete the work

In one day he does (1/4)th portion of the work

The Second Man (SM) takes 6 days to complete the work

In one day he does (1/6)th portion of the work

The FM and SM together do [ (1/4 ) + ( 1/6) ] th portion of the work

So , [ (3+2 )/12] = ( 5 / 12 ) = 5/12 th portion in one day

Hence, FM and SM together complete the work in 12/5 = 2.4 days

i am thinking c. sorry if im wrong .

step-by-step explanation:

(8+64)^2= 5184 < answer

step-by-step explanation:

2^3 = 8

4^3= 64

(8+64)^2 = 5184