Find the vertex and the axis of symmetry of the graph of y=-6(x+4)^2 – 3.

vertex = (- 4, - 3 ), equation is x = - 4

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = 6(x + 4)² - 3 ← is in vertex form

with (h, k ) = (- 4, 3 ) ← vertex

The equation of the axis of symmetry is a vertical line passing through the vertex, with equation

x = - 4

no solution exists the way you wrote the equation.