The sum of two complementary angles is 90° Angle A is represented by 3x - 10, and Angle B is represented by x. Solve for x Hint: combine the 2 angles and set equal to 90

Angle A = 3x - 10

Angle B = x

Their angle sum = 90° ( complementary angles form 90° )

This can be written in an equation as =

= 3x - 10 + x = 90

= 3x + × + ( -10 ) = 90

= 4x + (-10) = 90

= 4x = 90 + 10 ( transposing-10 from LHS to RHS changes-10 to +10 )

= 4x = 100

= x = 100 ÷ 4 ( transposing ×4 from LHS to RHS changes ×4 to ÷4 )

= x = 25

Angle A = 3x - 10

= 3 × 25 - 10

= 75 - 10

= Angle A = 65°

Angle B = x = 25°

Their sum = 65 + 25 = 90°

Therefore , the complementary angles , Angle A = 65° and Angle B = 25° .

true

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where's the diagram?

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