A certain pipe can fill up a tank 2 hours faster than another pipe. It takes 3 and hours for both pipes to fill up the same tank. In how many hours would the first pipe fill up the tank?

1 hour

Step-by-step explanation:

let the pipe take x hours to fill a house

then the second pipe will take=(x+2) hours

the combined time to fill up the house is 3 hours

so

1/(x+2)+1/2=1/3this is the combined work rate for both pipes

the lcm is 2(x+2)

(2+x+2)/2(x+2)=1/3

x+4/2(x+2)=3

cross multiply we have

x+4=3(x+2)

x+4=3x+6

3x+6-x-4=0

3x-x+6-4=0

2x+2=0

2x=-2

x=-1

The time is 1 hour

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

the answer is mp

step-by-step explanation: