Using the diagram below, what is the horizontal distance between the control tower and the plane?

x = 664.093 m

Step-by-step explanation:

tan∅ = opposite over adjacent

Since we are trying to find the horizontal distance, that means we are dealing with the bottom length and not the hypotenuse (the diagonal length):

Our theta (∅) = 52°

Our opposite = 850 m

Our adjacent = x m

tan52° = 850/x

xtan52° = 850

x = 850/tan52°

x = 664.093 m

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step-by-step explanation:

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step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v