What is an equation of the line that passes through the point (5, 1) and is parallel to the line x + y = 9?

Step-by-step explanation:

y = -x + 9

y - 1 = -(x - 5)

y - 1 = -x + 5

y = -x + 6

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

30

step-by-step explanation:

times by times