The crew on a fishing boat caught four fish that weighed a total of 1,080 pounds. The tarpon weighed twice as much as the amberjack
and the white marlin weighed twice
as much as the tarpon. The weight of the tuna was 5 times the weight of the
amberjack
How much did each fish weigh?
The amberjack weighed
pounds.
The tarpon weighed
pounds.
The marlin weighed
pounds.
The tuna weighed
pounds.
Kk

Step-by-step explanation:

First, We highlight key details. Here we can use the information 1,080 pounds, tarpon weighed twice as much as the amberjack, the white marling weighed twice as much as the tarpon, and the tuna weighed 5 times the weight of the amber jack. AndI'm lost. Do you think you could help me figure it out by finding the first one? if you do that would be great, and I'll be sure to update my question. Thank you! ^^)

n

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!