A rule that airline pilots use to estimate outside temperature in degrees Fahrenheit at an altitude of h thousand feet is to double h, subtract 15, and multiply the result by -1. State a rule for the altitude in feet based upon the outside temperature. At what altitude is outside temperature about -51°F?

The altitude is 33 thousand feet at the given temperature

Step-by-step explanation:

We firstly would need to write out the rule.

We can do this by by doubling h, subtracting 15 and multiply the result by -1

Kindly note that h is in thousands of feet

That would be ;

T = (2 * h - 15) * -1

T = -1(2h - 15)

T = -2h + 15

T = 15 - 2h

So for the altitude in feet at a temperature of - 51 degrees Fahrenheit

We simply substitute the value of -51 for the temperature

So we have;

-51 = 15 - 2h

2h = 15 + 51

2h = 66

h = 66/2

h = 33 thousand feet

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

it is x=-4

step-by-step explanation: