The following sinusoid is plotted below. Complete the following steps to model the curve using the cosine function. 1.What is the phase shift, h, of this curve?
2.What is the vertical shift, k, of this curve?
3.What is the amplitude, a, of this curve?
4.What is the period and the frequency factor, b, of this curve?
5.Write an equation using the cosine function that models this data set.

A.) phase shift is h=6

B.) Vertical shift is 21 units down

C.) The amplitude is 5 from the midline at y= -21

D.) The period is 16 and the frequency factor is pi/8

E.) 5 cos(pi/8(x-6))-21

Step-by-step explanation:

Find your minimum and maximum values. This would help you find the amplitude and the vertical shift. To find amplitude, the formula is A= (absolute value) of the max minus the min and divide by 2. To find vertical shift, you add the max and min values and divide by 2. The period is the distance of the max and min values and then doubled. The distance was 8 units so the period was 16. To find frequency factor, just plug in your values. You know that the formula is Period= 2pi/b. So it would be 16= 2pi/b. The frequency factor should be pi/8 after you cross multiply and then divide. To write the equation, you substitute the values into the equation of acos(b(x-c))+d. Make sure to put parentheses or else the graph will look wrong.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

d

step-by-step explanation: