Ebony’s bank balance first reached $400 on Day 4. The last day her balance was $400 was Day 8. Determine B(5), B(6), and B(7). Explain how you determined these amounts.
B(5)=B(60)=B(7)=400
Estimate B(1), B(2), and B(3). Explain how you determined these amounts.
B(1)50*1+200=250
B(2)50*2+200=300
B(3)50*3+200=350
Jade said that the amount of money Ebony took out of her account each day between Day 8 and Day 12 was the same amount of money she put into her account each day between Day 0 and Day 4. Recall that Day 12 is when the balance first reached $0. Without doing any calculations, how could you show Jade why that cannot be true?

Match the following terms with their definitions. 1. bisector of a segment ray ba and ray bc are opposite rays if a, b, and c are collinear and b (the endpoint of both rays) is between a and c. 2. opposite rays a ray, , is the set of points beginning at point a and going infinitely in the direction of point b. 3. collinear points a line or segment that intersects the segment at its midpoint. 4. betweenness of points a set of two or more points all on the same line. 5. ray the distance between the endpoints of a segment. 6. space point b is between a and c if a, b, and c are collinear and the equation ab + bc = ac is true, where ab, bc, and ac are the distances between points a and b, b and c, and a and c, respectively. 7. midpoint of a segment a set of two or more points all on the same plane. 8. coplanar points the point on a segment that divides the segment into two equal segments. 9. length of a segment the set of all possible points. 10. line segment the set of two different endpoints and all points between them.

What is the equation of this graphed line? enter your answer in slope-intercept form in the box.

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.