Diego pays $4.50 for 3 pounds of bananas and 2 pounds of oranges. one pound of oranges cost $0.75 more than one pound of bananas let b represent the price per pound of bananas. Which equation represents the situation, and what is the price per pound of each fruit? 3b + 2b = 4.50; $0.90 per bananas, $0.90 per pound of oranges 3b + 2(0.75) = 4.50; $1.00 per bananas, $1.75 per pound of oranges 3b + 2(b + 0.75) = 4.50; $0.60 per bananas, $1.35 per pound of oranges 3b + 2b = 4.50; $1.35 per bananas, $0.60 per pound of oranges

Given:

Diego pays $4.50 for 3 pounds of bananas and 2 pounds of oranges.

One pound of oranges cost $0.75 more than one pound of bananas.

To find:

The equation which represents the situation, and what is the price per pound of each fruit.

Solution:

Let b represent the price per pound of bananas.

Cost of 3 pound of banana = $3b

One pound of oranges cost $0.75 more than one pound of bananas.

So, cost of one pound of oranges = $(b+0.75)

Cost of 2 pound of oranges = $2(b+0.75)

Diego pays $4.50 for 3 pounds of bananas and 2 pounds of oranges.

Therefore, the required equation is .

On solving the above equation, we get

Divide both sides by 5.

Now,

Therefore, the price of fruits are $0.60 per bananas, $1.35 per pound of oranges.

Hence, the correct option is C.

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