Mis the midpoint of AN, A has coordinates (-5,-5) and M has coordinates (3, 4) Find the coordinates of N. 9

N(11 , 13)

Step-by-step explanation:

M(3,4) = (x,y)

A(-5, -5) = (x1,y1)

N (  )=(x2,y2)

using midpoint formula;

M(x,y)=(x1 + x2)/2 , (y1 + y2)/2

(3,4)= (-5 + x2)/2 , (-5 + y2)/2

Now;

3 = (-5+x2)/2                                                      4 = (-5 +y2)/2

6 = -5 +x2                                                            8 = -5 +y2

6+5 = x2                                                               8+5=y2

x2=11                                                                    y2 = 13

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15