I need help
a)104
b)128
c)120
d)74
e)87

m∠JTS = 104° ⇒ (A)

Step-by-step explanation:

The measure of an exterior angle of a triangle at one of its vertices equals the sum of the measures of the opposite interior angles.

Let us use this fact to solve the question

In ΔTSR

∵ T ∈ ray RJ

∴ ∠JTS is an exterior angle of ΔTSR

→ By using the fact above

∴ ∠TSR and ∠TRS are the opposite interior angles to ∠JTS

∴ m∠JTS = m∠TSR + m∠TRS

∵ m∠JTS = 27x - 4

∵ m∠ TSR = 30°

∵ m∠TRS = 18x + 2

→ Substitute their values in the equation above

∴ 27x - 4 = 30 + 18x + 2

→ Add the like terms in the right side

∴ 27x - 4 = 18x + 32

→ Add 4 to both sides

∴ 27x = 18x + 36

→ Subtract 18x from both sides

∴ 9x = 36

→ Divide both sides by 9

∴ x = 4

→ To find m∠JTS substitute x by 4 in its measure

∴ m∠JTS = 27(4) - 4 = 108 - 4

∴ m∠JTS = 104°

there is no question content here, but you for the free points! : d