Two groups of students were asked how far they lived from their school. The table below shows the distances in miles: Group A (distance in miles) 1 1.5 8 9.2 6.8 4.5 4.8 2.5 0.76
Group B (distance in miles) 2 2.5 3.23 1.3 1.8 2.4 3 1.5 1.8

Which statement best compares the mean distances for the two groups?
It is equal for Group A and Group B.
It is greater for Group B than Group A.
The value for group A is double the value for Group B.
The value for group B is three times the value for Group A.

C. The value for Group A is double the value for Group B

Step-by-step explanation:

First, you add all the numbers from each group.

A: The distance in total is 39.06

B: The distance in total is 19.53

To find the mean, which is another way of saying the average, you divide the sum with how many numbers there are. (hope this makes sense, I suck at wording)

A: There are 9 numbers in total, hence, 39.06/9 = 4.34

B: There are 9 numbers in total, hence, 19.53/9 = 2.17

Those are the mean distance for the two groups.

2.17 * 2 = 4.34

Hence, C (third statement)

go and ask your mom to you

the answer is; biodiversity resulting from few ancestors

adaptive radiation occurs when a population is subjected to a large natural environment with spatial ecological variations. the parts of the population in the different ecologies begin to adapt to their local environments. due to non-random mating across the large populations, this causes the different populations from the large population to speciate within their local environments. they, therefore, diverge to different species sharing a common ancestor.