(4s+3)(4s–3) i really neeed help

16s^2 -9

Step-by-step explanation:

(4s+3)(4s–3)

FOIL

first : 4x*4x = 16s^2

outer -3 *4s = -12s

inner 3*4s = 12s

last = 3* -3 = -9

Add them together

16s^2 -12s+12s -9

Combine like terms

16s^2 -9

d? maybe

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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