Consider the graph of the sixth-degree polynomial function f. Replace the values b, c, and d to write function f.
f(x)=(x-b)(x-c)^2(x-d)^3

f(x)=(x-1)(x+1)^2(x-4)^3

Step-by-step explanation:

The zeros of the function are x=-1, x=1, and x=4, so its factors are x+1, x-1, and x-4.

The graph touches, but doesn’t cross, the x-axis at x=-1. So the factor x+1 is a repeated factor with an even multiplicity.

The graph crosses the x-axis at x=4, but with a little curve before and after it meets this point. So the factor x+4 is a repeated factor with odd multiplicity.

The graph crosses the x-axis at x=1 with no curve before or after. So the factor x-1 is not a repeated factor.

Therefore, function f is defined by f(x)=(x-1)(x+1)^2(x-4)^3.

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole