Maya has a smart phone data plan that costs $50 per month that includes 2 GB of dat, but will charge extra $15 per GB over the included amount. How much would Maya have to pay in a month where she used 3 GB over a limit? How much would maya have to pay in a month where she used over by x GB?

a. $65

b. $(50 + 15x)

Step-by-step explanation:

A. From the question, we are told that the first 2 GB of data costs $50 while the subsequent extra GB cost $15 per GB

so for 3 GB, the normal $50 is charged for the first 2 GB while an extra $15 is charged for the extra 1 GB

so, the total amount charged for 3 GB will be $50 + $15 = $65

B. Amount to be paid in a month where x GB is used over the normal

Firstly, she will pay the $50 , then for the extra she will be paying $15 * x = $15x

So the amount to be paid will be;

$50 + $15x = $(50 + 15x)

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i