Godric has 11 bills in his wallet. Each bill is either a $5 dollar or a $20 dollar. Godric has a total of $115 in his wallet. A) Could Godric have five $20 bills given the information you know?Explain

B) Let n be the number of five dollar bills that Godric has. Set up an equation using n that models this situation and solve it for n

A) Godric can have maximum of four $20 bills.

Therefore Godric can not have five $20 bills.

B) Equation is:

Step-by-step explanation:

Let the number of $5 bills with Godric =

Total number of bills = 11

Therefore, number of $20 bills = (11 - )

Total amount of money in form of $5 bills = $

Total amount of money in form of $20 bills = $

Total money with Godric is $115.

Number of $5 bills present with Godric = 7

Number of $20 bills present with Godric = 11 - 7 = 4

A) Godric can have maximum of four $20 bills.

Therefore Godric can not have five $20 bills.

B) Equation is:

Solution is

$20.01

step-by-step explanation:

the sale price is (1.00 - 0.77)($87), or 0.23($87), or $20.01.

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64