What is an equation of the line that passes through the point (-6, -2) and is parallel to the line 3x – 2y = 2?

y=3/2x+7

Step-by-step explanation:

To find the equation of the line that passes through the given point, let's first convert the given equation to slope-intercept form.

3x-2y=2           [subtract both sides by 3x]

-2y=-3x+2        [divide both sides by -2]

y=3/2x-1

Now that we have the equation in slope-intercept form, we know that the slope must stay the same because parallel lines NEVER touch. All we have to do is plug in the given point to find the y-intercept.

-2=3/2(-6)+b    [multiply]

-2=-9+b            [add both sides by 9]

b=7

Now, we know that the parallel equation is y=3/2x+7.

answer: i'm not sure

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)