subject
Mathematics, 13.10.2020 14:01 SithLeo

Given \sqrt{27}+\sqrt{108} 27

+
108


=27^{\frac{1}{2}}+108^{\frac{1}{2}} =27
2
1


+108
2
1


3^{\frac{1}{2}}\cdot9^{\frac{1}{2}} +3^{\frac{1}{2}}\cdot36^{\frac{1}{2 }}3
2
1


β‹…9
2
1


+3
2
1


β‹…36
2
1


3\cdot3^{\frac{1}{2}}+6\cdot3^{\fra c{1}{2}}3β‹…3
2
1


+6β‹…3
2
1


18\cdot3^{\frac{1}{2}}18β‹…3
2
1

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Answers: 2

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Given \sqrt{27}+\sqrt{108} 27

+
108


=27^{\frac{1}{2}}+108^{...
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