Triangle pqr has vertices p(–2, 6), q(–8, 4), and r(1, –2). it is translated according to the rule (x, y) → (x – 2, y – 16). what is the y-value of p'? the y-value of p' is

For the question "Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). What is the y-value of P'? The y-value of P' is" To get the y-value of P'. Translation of the vertices of triangle PQR using the rule (x, y) → (x – 2, y – 16) means that the x-value is translated 2 units to the left (reducing the x-value by 2) and the y-value is translated 16 units down (reducing the y-value by 16). Thus, the coordinate of P' is (-2 - 2, 6 - 16) = (-4, -10). Therefore, the y-value of P'is (-4, -10)