Find the equation of the circle that passes through the point (-3,1) and has its center at C(-4,6)

(x+4)^2 + (y-6)^2 = 29

Step-by-step explanation:

The center-radius form of the circle equation is in the format (x – h)^2 + (y – k)^2 = r^2, with the center being at the point (h, k)

Replacing the center C(-4,6):

(x+4)^2 + (y-6)^2 = r^2

then replacing the point (-3,1):

(-3+4)^2 + (1-6)^2 = r^2

1 + 25 = r^2

then the equation of the circle is:

(x+4)^2 + (y-6)^2 = 29

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above