I really need help it's due today at 2:00 1.Find the value of f(–9) and g(1) if f(x) = 8x + 6 and g(x) = 9x + 20x−2
A. f(–9) = 14
g(1) = 30

B. f(–9) = –78
g(1) = –11

C. f(–9) = –66
g(1) = 29

D. f(–9) = 8
g(1) = –80.75

2.Find the value of f(–9) and g(–1) if f(x) = –3x – 2 and g(x) = 3x3 – 24x .

A. f(–9) = 25
g(–1) = 21

B. f(–9) = –5
g(–1) = 20

C. f(–9) = 29
g(–1) = 26

D. f(–9) = 3
g(–1) = –27

c

Step-by-step explanation:

Hope this helps

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )