What are the x and y intercepts for 3x-6y=-48

x- intercept = - 16, y- intercept = 8

Step-by-step explanation:

Given

3x - 6y = - 48

To find the x- intercept, let y = 0 in the equation and solve for x

3x - 6(0) = - 48 , that is

3x - 0 = - 48 ( divide both sides by 3 )

x = - 16 ← x- intercept or (- 16, 0 )

To find the y- intercept, let x = 0 in the equation and solve for y

3(0) - 6y = - 48 , that is

0 - 6y = - 48 ( divide both sides by - 6 )

y = 8 ← y- intercept or (0, 8 )

correct answers below:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right