*Two buses were coming from two different places situated just in the opposite direction. The average speed of one bus is 5 km/hr more than that of another on
and they had started their journey in the same time. If the distance between
places is 500 km and they meet after 4 hours, find their speed.

 60 km/hr and 65 km/hr

Step-by-step explanation:

        o←500→o

        Bus 1: rate = r + 5                                              Bus 2: rate = r            

                  time = 4                                                               time = 4

                  distance = d                                                        distance = 500 - d

                              Use distance = rate x time

      Bus 1: d = 4(r + 5)                                               Bus 2: 500 - d = 4(r)

                d = 4r + 20                                                    -d = 4r - 500

                                                                                      d = 500 - 4r

Solve the System of Equations using the Substitution method:

                                    4r + 20 = 500 - 4r

                                    8r + 20 = 500

                                   8r          = 480

                                              r = 60

    Bus 1: rate = r + 5                                              Bus 2: rate = r

                     = 60 + 5                                                              = 60

                     = 65

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."