Suppose that a family has 5 children. Also, suppose that the probability of having a boy is 1/2. Find the probability that the family has no more than 3 boys.

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Step-by-step explanation:

P(X≤6) equals 8C0(1/2)0(1/2)8 + 8C1(1/2)1(1/2)7 + 8C2(1/2)2(1/2)6 + 8C3(1/2)3(1/2)5 + 8C4(1/2)4(1/2)4 + 8C5(1/2)5(1/2)3 + 8C6(1/2)6(1/2)2 where nCs(p)s(1-p)(n-s) translates to n!÷s!÷(n-s)!×ps×(1-p)(n-s).

damm bro the struggle

step-by-step explanation: