An auto parts manufacturer throws out gaskets with weights that are not within 0.06 pound of the mean weight of the batch. The weights (in pounds) of the gaskets in a batch are 0.58, 0.63, 0.65, 0.53, and 0.61. Which gasket(s) should be thrown out?

0.53 will not chosen

Step-by-step explanation:

Given weights:

0.58, 0.63, 0.65, 0.53, and 0.61.

Computation:

Mean weight X = [0.58+0.63+0.65+0.53+0.61] / 5

Mean weight X = [3] / 5

Mean weight X = 0.60

Acceptable weight = l x-X l < 0.06

l x-0.60 l < 0.06

So solving inequality

0.54 < x < 0.66

So, 0.53 will not chosen.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

what's the question?

step-by-step explanation:

there is no question.