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Mathematics, 12.10.2020 22:01 rboehm59

Solve: 23a + 6 > 0 a>9A is greater than 9

a βˆ’9A is greater than negative 9

a<βˆ’9

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Answers: 1

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Solve: 23a + 6 > 0 a>9A is greater than 9

a βˆ’9A is greater than negative 9
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