Point U is on line segment \overline{TV}
TV
. Given TV=x+10,TV=x+10, TU=3x-8,TU=3xβ8, and UV=...
Mathematics, 12.10.2020 21:01 brooke0713
Point U is on line segment \overline{TV}
TV
. Given TV=x+10,TV=x+10, TU=3x-8,TU=3xβ8, and UV=10,UV=10, determine the numerical length of \overline{TV}.
TV
.
Answers: 3
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