The width of a rectangle is four feet more than six times its length, L. If the perimeter of the rectangle is 568 feet, what is the length of the rectangle?

Hi there!

Your answer is:

The length is 40

Step-by-step explanation:

W=4+6L

P=568

Perimeter formula

W+W+L+L=568

Plug in known values!

(4+6L)+(4+6L) + L +L = 568

Solve for L

14L + 8 = 568

-8

14L = 560

/14

L=40

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6