Factorise m^3+m
Factorise 25-y^2
Factorise x^2+3x-28

1. m³ + m

= m( m² + 1) [ a² + b²]

= (a-b)² + 2ab

= m { (m –1)² + 2× m × 1 }

= m { ( m–1)² + 2m}

2. 25 – y² [ a² – b²]

= 5² – y²

= (5+y) (5–y)

3. x² + 3x –28 [ middle term factorisation]

= x² + 7x –4x –28

= x( x +7) –4 ( x + 7 )

= ( x–4) (x+7)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.