Evaluate and solve for the variable 1.)–2 = y + 5 (2.) x – 7 = 4 + 10(3.)–2x + 3x – 5 = 6 – 21 (4.) 70 = 7m (5.)4 – 14 = 5x

(6.)2y + 3y = 4 – 6 – 13 (7.)–z = 8 (8.)12 – c = 8 (9.)7 = 5b (10.) 8=g/4 (11.) f + 4 = –6 (12.)7 = y – 2 (13.)–12 = x + 4 (14.)3y = –18 (15.)–4 – 10 = 4y + 3y

(16.)–42 + 20 = –2x + 13x (17.)7x + 8x = 12 + (–12) (18.)23x – 25x = 7 – 9

Write four different equations that have –3 as the solution.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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