A bag contains 4 blue marbles, 9 green marbles, and 5 red marbles. One marble is drawn from the bag. What is the probability that the marble drawn is not blue?

4blue marble+9 green marble+5 red marble=18marble totle

1 marble probility=1/17

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)