Name the line of reflection used to map each pre-image to its image.
Please help

Step-by-step explanation:

From the picture attached,

9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.

    Therefore, line of reflection will be x = -2

10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,

y = x.

11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.

12). Line passing through midpoint of the line joining BB' will be the line of reflection.

Coordinates of B → (5, 3)

Coordinates of B' → (5, 7)

Coordinates of BB' → → (5, 5)

Therefore, line of reflection will be y = 5.

13). Coordinates of G → (2, 5)

     Coordinates of G' → (-2, 5)

     Midpoint joining the segment GG' → → (0, 5)

     Therefore, line of reflection → x = 0

14). Line of reflection passing through (0, 0) and slope = -1

     y = -x

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)