Two cars travel at the same distance. The first car travel at 50 miles per hour and reaches its destination at t hours. The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car how long does it take for the first car to reach its destination

It would take the first car 6 hours to reach its destination.

Speed is the ratio of distance to time. It is given by:

Speed = distance /time

Since the two cars travel at the same distance, let d represent this distance.

The first car travel at 50 miles per hour and reaches its destination at t hours. Hence:

50 = d / t

d = 50t   (1)

The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car. Hence the time = t - 1. Hence:

60 = d / (t - 1)

d = 60(t - 1)

d = 60t - 60   (2)

Equating both equations gives:

50t = 60t - 60

10t = 60

t = 6 hours

Hence it would take the first car 6 hours to reach its destination

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The first car reaches its destination in 6 hours.

Step-by-step explanation:

Speed of the first car = 50 miles per hour

Time taken = t hours

Distance travelled = Speed × Time = 50 t

Speed of the second car = 60 miles per hour

Time taken = hours

Distance travelled = Speed × Time =

As two cars travel the same distance,

So, the first car reaches its destination in 6 hours.

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sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: