physics convention 11 companies set up equal sized square booths in a row along one wall of a convention center. The booths are adjacent to each other and a 2-ft wide walkway surrounds the block of booths on three sides. The total area of the booths and walkway is 1200 ft^2. What is the side length of each booth?

Side length of each booth is 8.35 ft approximately.

Step-by-step explanation:

There are 11 companies set up equal sized square booths in a row along one wall of a convention center.

Now, refer the diagram to answer the problem.

It is given area is 1200.

So, length x width =1200

(11x+24)(x+2)=1200

Multiply using FOIL method.

+22x+24x+48=1200

+46x+48-1200=0

+46x-1152=0

Solve using quadratic formula

x=

x=

x=

Simplify it

Simplify to get two values for x.

x=8.35; x=-12.67

Here negative does not work.

Side length of each booth is 8.35 ft.

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation:

step-by-step explanation: