Jada earned $50 babysitting and plans to use the money to go to the fair l. admission to the fair is $5 and each ride is $2.50.while at the fair she buys a funnel cake for $3.what is the maximum number of rides jada can ride?

The maximum number of rides is 16

Step-by-step explanation:

She has a total of $50 and spends $3 for the cake and $5 for admission. She has to spend $2.50 for every ride.

Your equation would be set up as:

$50=$5+$3+$2.50x

You would combine like terms and get

$50=$8+$2.50x

Subtract the $8 from $50 and you get

$42=$2.50x

Divide each number by 2.50 and you get

16.8=x, you cannot have a decimal as an answer since she cannot ride eight tenths of a ride so the maximum number of rides is 16

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: 88

step-by-step explanation: