Identify the error or errors in this argument that supposedly shows that if ∀x(P(x) ∨ Q(x)) is true then ∀xP(x) ∨ ∀xQ(x) is true. 1. ∀x(P(x) ∨ Q(x)) Premise 2. P(c) ∨ Q(c) Universal instantiation from (1) 3. P(c) Simplification from (2) 4. ∀xP(x) Universal generalization from (3) 5. Q(c) Simplification from (2) 6. ∀xQ(x) Universal generalization from (5) 7. ∀x(P(x) ∨ ∀xQ(x)) Conjunction from (4) and (6) 25. Justify the rule of universal modus tollens by showin

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

Y= -2x-1 the negative in front of the 2 is because the slope is negative and the -1 is because it’s down 1 on the y axis.

First, think of what you know. you know that the number t the end of the equation will need to be subtracted because it is the money he lost from buying the lawn mower. and your first two weeks have negative profit, so that tells you that c and d are wrong. now you can plug any of the weeks into a and b to see which one works. i'll start with plugging week 1 into a.this isn't right because it says your answer for week one should be -90.so now we need to try the same thing with b.this one got you the right answer, (sometimes if you only check with one of the weeks multiple will work so you need to check with more of the weeks, but it worked out fine here)this means that b is the correct answer.let me know if you need more clarification. i hope this : )