Let p=x^2+6p=x 2 +6p, equals, x, start superscript, 2, end superscript, plus, 6. Which equation is equivalent to (x^2+6)^2-21=4x^2+24(x 2 +6) 2 ?21=4x 2 +24left parenthesis, x, start superscript, 2, end superscript, plus, 6, right parenthesis, start superscript, 2, end superscript, minus, 21, equals, 4, x, start superscript, 2, end superscript, plus, 24 in terms of p ?

(p+3)(p-7) = 0

Step-by-step explanation:

Given p=x^2+6p and (x^2+6)^2-21=4x^2+24

We are to substitute the the p = x²+6 into the expression as shown;

The expression (x^2+6)^2-21=4x^2+24 will become

(x²+6)²-21 = 4(x²+6)

On substituting p, the expression becomes;

p²-21 = 4p

Subtract 4p from both sides

p²-21-4p = 4p-4p

p²-4p-21 = 0

p²-7p+3p-21 = 0

p(p-7)+3(p-7) = 0

(p+3)(p-7) = 0

Hence the expression in terms of p is (p+3)(p-7) = 0

i not know

step-by-step explanation:

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950