A square has a diagonal that measures 18 inches. To the nearest tenth, what is the length of one side of the square?

18/sqrt(2)

Step-by-step explanation:

Divide the square into two congruent right triangles:

a and b are the sides of the triangle

since we know that a=b

then the right triangle is isosceles

meaning that the theorem of the 45-45-90 triangle is applicable

so then we can say that 18/sqrt(2) = a = b

i hope this is what you were looking for.

see attached graph

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8