In a standardized IQ test, scores are normally distributed with a mean score of 100 and a standard deviation of 15. Find the probability that a randomly selected person has an IQ score higher than 125.

0.0475

Step-by-step explanation:

First find the z-score.

z = (x − μ) / σ

z = (125 − 100) / 15

z = 1.67

Use a calculator or chart to find the probability.  Using a chart:

P(Z > 1.67) = 1 − P(Z < 1.67)

P(Z > 1.67) = 1 − 0.9525

P(Z > 1.67) = 0.0475

answer

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step-by-step explanation:

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