Line JM intersects line GK at point N. Horizontal line G K intersects vertical line J M at point N, forming a right angle. A line extends from point N to L, down and to the right.
Which statements are true about the figure? Select two options.

AngleGNJ is complementary to AngleJNK.
AngleMNL is complementary to AngleKNL.
AngleMNG is complementary to AngleGNJ.
AngleKNJ is supplementary to AngleMNL.
AngleGNM is supplementary to AngleJNK.

  AngleMNL is complementary to AngleKNL.

  AngleGNM is supplementary to AngleJNK

Step-by-step explanation:

Ray NL creates two angles in the lower right quadrant. They total 90°, so the two angles formed are complementary. The relation is ...

  ∠MNL + ∠KNL = ∠MNK = 90°

Hence ∠MNL and ∠KNL are complementary.

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∠GNM and ∠JNK are both right angles (and also vertical angles). Because their sum is 180°, they can be said to be supplementary.

∠GNM and ∠JNK are supplementary.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

1.true 2.false? ? i think. .

step-by-step explanation: