This equation models the height over time of a deep-water sensor. h(t) = -4.9t^2 + 29.4t + 5.9
Rewrite the function in vertex form.

h(t) =  -4.9(t - 3)^2 + 50.

Step-by-step explanation:

h(t) = -4.9t^2 + 29.4t + 5.9

h(t) =  -4.9(t^2 - 6t) + 5.9       Complete the square on t^2 - 6t:

h(t) = -4.9[ (t - 3)^2 - 9] + 5.9

h(t) = -4.9(t - 3)^2 + 44.1 + 5.9

h(t) =  -4.9(t - 3)^2 + 50

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

no this is a nonlinear negative